document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=47737>Question 47737</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I have cylinder on its side holding a liquid. the volume of the cylinder is no problem to determine but i need help as the volume in the  tank   drops.  Cylinder measures 11 ft x 4ft<BR>\n" );
document.write( "and current tank level is 1 ft or three ft down. What is the volume in tank at 1 ft?  What is the calculation to determine volume at different tank levels? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #31533 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=31533\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I have cylinder on its side holding a liquid. the volume of the cylinder is no problem to determine but i need help as the volume in the tank drops. Cylinder measures 11 ft x 4ft<BR>\n" );
document.write( "and current tank level is 1 ft or three ft down. What is the volume in tank at 1 ft? What is the calculation to determine volume at different tank levels?<BR>\n" );
document.write( "GOOD QUESTION.THE METHOD IS TO FIND CROSS SECTION AREA OF THE CYLINDER AT ANY TIME.WHEN FULL IT IS CIRCLE WITH RADIUS = 2'..BUT WHEN LEVEL DROPS BY 3',IT IS A SECTOR .SINCE A SECTOR IS A PART OF THE CIRCLE ,ITS AREA IS DETERMINED AS A FRACTION OF THE TOTAL ARE OF CIRCLE<BR>\n" );
document.write( "TOTAL AREA OF CIRCLE =PI*R^2...FOR A 360 DEGREE ANGLE AT THE CENTRE.<BR>\n" );
document.write( "AREA OF CIRCLE FORMING X DEGRES AT CENTRE =(X/360)*PI*R^2\r<BR>\n" );
document.write( "\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+graph%28+600%2C+600%2C+-10%2C+10%2C+-10%2C+10%2C+%284-x%5E2%29%5E0.5%2C+-%284-x%5E2%29%5E0.5%2Cx%2F3%5E0.5%2C-x%2F3%5E0.5%2C-1%29+ ALIGN=MIDDLE   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "IF YOU KNOW TRIGNOMETRY THIS ANGLE IS FOUND AS FOLLOWS.<BR>\n" );
document.write( "LET CENTRE BE O AND WATER LEVEL BE AB .LET D BE THE MIDPOINT OF AB.<BR>\n" );
document.write( "ODA IS A RIGHT ANGLED TRIANGLE WITH ANGLE ADO=90<BR>\n" );
document.write( "OA=2<BR>\n" );
document.write( "OD=2-1=1<BR>\n" );
document.write( "HENCE AD = SQRT(2^2-1^2)=SQRT(3)<BR>\n" );
document.write( "AD/OA=SQRT(3)/2=SIN(ANGLE AOD)<BR>\n" );
document.write( "ANGLE AOD =60 DEG.<BR>\n" );
document.write( "ANGLE AOB =2 *60=120<BR>\n" );
document.write( "HENCE AREA OF CROSS SECTION OF WATER IN THE TANK IS (120/360)*PI*2^2=4PI/3<BR>\n" );
document.write( "VOLUME = LENGTH*AREA OF CROSS SECTION = 11*4PI/3=44PI/3 </SPAN>\n" );
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