document.write( "Question 459473: Find three consecutive odd integers whose sum is 111. Are there three consecutive odd integers whose sum is 1111? Explain \n" ); document.write( "

Algebra.Com's Answer #315325 by richard1234(7193) $\"\"$ $\"About$

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We could let x-2, x, x+2 be the integers that sum up to 111 (x is an odd integer), so\r
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\n" ); document.write( "\n" ); document.write( "(x-2) + x + (x+2) = 111\r
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\n" ); document.write( "\n" ); document.write( "3x = 111 --> x = 37\r
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\n" ); document.write( "\n" ); document.write( "There are no three consecutive odd integers that sum to 1111. From the previous example we got 3x = 111. 111 is a multiple of 3 so this works out. However, 1111 is not a multiple of 3, so this would imply that x is not an integer, contradiction. \n" ); document.write( "

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