document.write( "Question 47723: sqrt of 4x + 1 + 3 = 0 \n" ); document.write( "

Algebra.Com's Answer #31531 by venugopalramana(3286) $\"\"$ $\"About$

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sqrt of 4x + 1 + 3 = 0
\n" ); document.write( "sqrt(4x)=-4
\n" ); document.write( "4x=(-4)^2=16
\n" ); document.write( "x=16/4=4..if we resubstitute it will result in
\n" ); document.write( "sqrt(16)=-4
\n" ); document.write( "normally we take sqrt(x) as a positive square root.but here it has tobe taken as negative sq.rt \n" ); document.write( "

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