document.write( "Question 459794: Write the slope-intercept equation for the line that passes through (-9,9) and is perpendicular to -9x-2y=10. Please show the steps \n" ); document.write( "
Algebra.Com's Answer #315307 by nerdybill(7384)\"\" \"About 
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Write the slope-intercept equation for the line that passes through (-9,9) and is perpendicular to -9x-2y=10. Please show the steps
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\n" ); document.write( "Begin by finding the slope of:
\n" ); document.write( "-9x-2y=10
\n" ); document.write( "do this, by putting it into \"slope-intercept\" form:
\n" ); document.write( "-9x-2y=10
\n" ); document.write( "-2y=9x+10
\n" ); document.write( "y=(-9/2)x-5
\n" ); document.write( "slope is -9/2
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\n" ); document.write( "Slope of our new line has be the \"negative reciprocal\" for it to be perpendicular.
\n" ); document.write( "(-9/2)m = -1
\n" ); document.write( "m = 2/9 (our new slope)
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\n" ); document.write( "Plug the above slope and the point (-9,9) into the \"point-slope\" form:
\n" ); document.write( "y - y1 = m(x - x1)
\n" ); document.write( "y - 9 = (2/9)(x - (-9))
\n" ); document.write( "y - 9 = (2/9)(x + 9)
\n" ); document.write( "y - 9 = (2/9)x + 2
\n" ); document.write( "y = (2/9)x + 2 + 9
\n" ); document.write( "y = (2/9)x + 11 (this is what they're looking for)\r
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