document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=459779>Question 459779</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if 3 times the square root of 7 divided by \"a\" times the square root of 7 equals 3 times the sqaure root of 7 divided by 7 is true then a must equal?\r<BR>\n" );
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document.write( " i really cant figure out how to do this but  would really appreciate it if you could help explain.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #315296 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=315296\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> if 3 times the square root of 7 divided by \"a\" times the square root of 7 equals 3 times the sqaure root of 7 divided by 7 is true then a must equal? <BR>\n" );
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document.write( "(3sqrt(7)]/[a*(sqrt(7)] = [3sqrt(7)]/7<BR>\n" );
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document.write( "Cross-multiply to get:<BR>\n" );
document.write( "21sqrt(7) = 3a*sqrt(7)<BR>\n" );
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document.write( "Divide both sides by 3*sqrt(7) to get:<BR>\n" );
document.write( "7 = a<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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