document.write( "Question 47164: The length of a rectangle is twice the width. The perimeter is 36 units. What are the length and width? \n" ); document.write( "
Algebra.Com's Answer #31524 by mszlmb(115)![]() ![]() You can put this solution on YOUR website! perimeter=2length+2width\r\n" ); document.write( "\r\n" ); document.write( "2width=1length.\r\n" ); document.write( "\r\n" ); document.write( "ok let's replace width with w and length with l. It is also safe to replace perimeter with 36 as that is its value.\r\n" ); document.write( "\r\n" ); document.write( "36=2l+2w\r\n" ); document.write( "2w=l\r\n" ); document.write( "\r\n" ); document.write( "so let's substitute l with 2w in the first problem.\r\n" ); document.write( "\r\n" ); document.write( "36=2(2w)+2w simplify\r\n" ); document.write( "36=6w divide by 6, both sides\r\n" ); document.write( "6=w\r\n" ); document.write( "\r\n" ); document.write( "back to second equation:\r\n" ); document.write( "2w=l\r\n" ); document.write( "\r\n" ); document.write( "2(6)=l\r\n" ); document.write( "12=l\r\n" ); document.write( "\r\n" ); document.write( "length=12\r\n" ); document.write( "width=6.\n" ); document.write( " |