document.write( "Question 459681: ONE NUMBER IS 4 LESS THAN THE SECOND NUMBER. THREE TIMES THE FIRST NUMBER IS 14 MORE THAN 4 TIMES THE SECOND NUMBER. FIND THE FIRST AND SECOND NUMBER. \r
\n" ); document.write( "\n" ); document.write( "PLEASE HELP ; ) THANK YOU!!
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Algebra.Com's Answer #315231 by sudhanshu_kmr(1152)\"\" \"About 
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\n" ); document.write( "Let first number is x, second is y.\r
\n" ); document.write( "\n" ); document.write( "x = y-4 \r
\n" ); document.write( "\n" ); document.write( "3x = 14+ 4y\r
\n" ); document.write( "\n" ); document.write( "so, 3(y-4) = 14 + 4y\r
\n" ); document.write( "\n" ); document.write( "=> 3y -12 = 14 + 4y\r
\n" ); document.write( "\n" ); document.write( "=> y = -26 \r
\n" ); document.write( "\n" ); document.write( "x = -30 \r
\n" ); document.write( "\n" ); document.write( "first is -30, second is -26 .\r
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