document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=459648>Question 459648</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Jane is thinking of a number such that 3 less than twice that number is the additive inverse of 7.<BR>\n" );
document.write( "What is the number?\r<BR>\n" );
document.write( "\n" );
document.write( "Which inverse operation in the correct sequence will solve the riddle?\r<BR>\n" );
document.write( "\n" );
document.write( "A.  Add 3; then multiply by 2\r<BR>\n" );
document.write( "\n" );
document.write( "B.  Add 3;  then divide by 2\r<BR>\n" );
document.write( "\n" );
document.write( "C.  Multiply by 1/2, than subtract 3.\r<BR>\n" );
document.write( "\n" );
document.write( "D.  Multiply by 1/2, then divide by 3. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #315223 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=315223\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2x-3=-7<BR>\n" );
document.write( "b)<BR>\n" );
document.write( "add 3<BR>\n" );
document.write( "2x=-4<BR>\n" );
document.write( "divide by 2<BR>\n" );
document.write( "x=-2<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );