document.write( "Question 459676: find the value of x to 3 d.p when:\r
\n" ); document.write( "\n" ); document.write( "x^2 + 20x = 400cm^2
\n" ); document.write( "

Algebra.Com's Answer #315215 by Alan3354(69443)\"\" \"About 
You can put this solution on YOUR website!
x^2 + 20x = 400cm^2
\n" ); document.write( "Units aren't usual in a quadratic.
\n" ); document.write( "x^2 + 20x - 400 = 0
\n" ); document.write( "\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "
Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc)
Quadratic equation \"ax%5E2%2Bbx%2Bc=0\" (in our case \"1x%5E2%2B20x%2B-400+=+0\") has the following solutons:
\n" ); document.write( "
\n" ); document.write( " \"x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
\n" ); document.write( "
\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
\n" ); document.write( "
\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%2820%29%5E2-4%2A1%2A-400=2000\".
\n" ); document.write( "
\n" ); document.write( " Discriminant d=2000 is greater than zero. That means that there are two solutions: \"+x%5B12%5D+=+%28-20%2B-sqrt%28+2000+%29%29%2F2%5Ca\".
\n" ); document.write( "
\n" ); document.write( " \"x%5B1%5D+=+%28-%2820%29%2Bsqrt%28+2000+%29%29%2F2%5C1+=+12.3606797749979\"
\n" ); document.write( " \"x%5B2%5D+=+%28-%2820%29-sqrt%28+2000+%29%29%2F2%5C1+=+-32.3606797749979\"
\n" ); document.write( "
\n" ); document.write( " Quadratic expression \"1x%5E2%2B20x%2B-400\" can be factored:
\n" ); document.write( " \"1x%5E2%2B20x%2B-400+=+%28x-12.3606797749979%29%2A%28x--32.3606797749979%29\"
\n" ); document.write( " Again, the answer is: 12.3606797749979, -32.3606797749979.\n" ); document.write( "Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+1%2Ax%5E2%2B20%2Ax%2B-400+%29\"

\n" ); document.write( "\n" ); document.write( "---------
\n" ); document.write( "x = 12.36 cm
\n" ); document.write( "x = -32.36 cm
\n" ); document.write( "Good luck with the -32 cm
\n" ); document.write( "
\n" ); document.write( "
\n" );