document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=459531>Question 459531</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How many liters of pure acetic acid must be mixed with 10 liters of a 30% acetic acid soluti0n to get a 60% soluti0n? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #315176 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=315176\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x=amount of pure acetic acid needed<BR>\n" );
document.write( "Now we know that the amount of pure acetic acid that exists before the mixture takes place (x+0.30*10) has to equal the amount of pure acetic acid after the mixture takes place (0.60(x+10)).   Sooooo<BR>\n" );
document.write( "x+0.30*10=0.60(x+10) get rid of parens and simplify<BR>\n" );
document.write( "x+3=0.60x+6 subtract 3 and also 0.60x from each side<BR>\n" );
document.write( "x+3-3-0.60x=0.60x-0.60x+6-3  collect like terms<BR>\n" );
document.write( "0.40x=3<BR>\n" );
document.write( "x=7.5 liters----------------amount of pure acetic acid needed\r<BR>\n" );
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document.write( "CK<BR>\n" );
document.write( "7.5+0.30*10=0.60*17.5<BR>\n" );
document.write( "7.5+3=10.5<BR>\n" );
document.write( "10.5=10.5\r<BR>\n" );
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document.write( "Hope this helps---ptaylor<BR>\n" );
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