document.write( "Question 459612: I'm 46 years old and working on refreshing my skills. How do I solve this using the substitution method?\r
\n" ); document.write( "\n" ); document.write( "x=1/5y
\n" ); document.write( "3x+2y=26\r
\n" ); document.write( "\n" ); document.write( "Thanks
\n" ); document.write( "x=1/5y ...(1)
\n" ); document.write( "3x+2y=26 ...(2)
\n" ); document.write( "from eq(1)substituting the value of x in eq(2)
\n" ); document.write( "3/5y+2y=26
\n" ); document.write( "(3y+10y)/5=26
\n" ); document.write( "13y=26*5
\n" ); document.write( "y=10
\n" ); document.write( "and therefore x=2
\n" ); document.write( "

Algebra.Com's Answer #315150 by pallavi(12)\"\" \"About 
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