document.write( "Question 459588: Find a polynomial that represents the total surface area of the right circular cylinder with a radius of 4. \r
\n" );
document.write( "
\n" );
document.write( "\n" );
document.write( "Now use that polynomial to determine the total surface area of each of the following right circular cylinders that have a base with a radius of 4. Use 3.14 for π, and express the answers to the nearest tenth. \n" );
document.write( "
Algebra.Com's Answer #315144 by math-vortex(648)![]() ![]() You can put this solution on YOUR website! A right circular cylinder is a cylinder whose base is perpendicular to its sides (like a soup can.) The expression for the surface area has two parts: \n" ); document.write( "There is the rectangular-shaped side that wraps around the cylinder, and the circular base and top of the cylinder. \n" ); document.write( ". \n" ); document.write( "The surface area of the side is the height of the cylinder times the circumference of the base. In algebra, this translates to \n" ); document.write( ". \n" ); document.write( "(h)(2[pi]r) \n" ); document.write( ". \n" ); document.write( "where h is the height of the cylinder and r is the radius of its circular base. We know that the radius is 4 and we approximate [pi] as 3.14. This gives us \n" ); document.write( ". \n" ); document.write( "h(2)(3.14)(4) = (25.12)h\r \n" ); document.write( "\n" ); document.write( "The surface area of the base and top of the cylinder is the area of the circle. There are two circles so we multiply by 2. \n" ); document.write( ". \n" ); document.write( "(2)([pi])r^2 = (2)(3.14)(4^2) = 100.48 \n" ); document.write( ". \n" ); document.write( "We combine these expressions to create a polynomial for the surface area S in terms of the height of the cylinder. \n" ); document.write( "==== \n" ); document.write( "S = (25.12)h + 100.48 \n" ); document.write( "==== \n" ); document.write( "Your question does not include information about the other cylinders, but you can substitute their heights for h in the polynomial and get the surface area. \n" ); document.write( ". \n" ); document.write( "Good luck!\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |