document.write( "Question 47677This question is from textbook Introductory Algebra
\n" ); document.write( ": A car and a bus leave a town at 1 pm and head for a town 300 miles away. The rate of the car is twice the rate of the bus. The car arrives 5 hours ahead of the bus. Find the rate of the car. \n" ); document.write( "
Algebra.Com's Answer #31513 by stanbon(75887)\"\" \"About 
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A car and a bus leave a town at 1 pm and head for a town 300 miles away. The rate of the car is twice the rate of the bus. The car arrives 5 hours ahead of the bus. Find the rate of the car.\r
\n" ); document.write( "\n" ); document.write( "Bus DATA:
\n" ); document.write( "distance=300 mi; rate = x mi/hr; time=d/r = (300/x) hr.\r
\n" ); document.write( "\n" ); document.write( "Car DATA:
\n" ); document.write( "distance=300 mi; rate = rate = 2x mi/hr ; time = d/r = 300(2x) hr.\r
\n" ); document.write( "\n" ); document.write( "EQUATIOn:
\n" ); document.write( "car time = bus time - 5 hr.\r
\n" ); document.write( "\n" ); document.write( "300/2x = 300/x - 5
\n" ); document.write( "Divide thru by 300 to get:
\n" ); document.write( "1/2x = 1/x - 1/60
\n" ); document.write( "Multiply thru by 2x to get:
\n" ); document.write( "1 = 2 - x/30
\n" ); document.write( "-1=-x/30
\n" ); document.write( "x=30
\n" ); document.write( "2x=60 mph (The rate of the car)
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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