document.write( "Question 47677This question is from textbook Introductory Algebra
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document.write( ": A car and a bus leave a town at 1 pm and head for a town 300 miles away. The rate of the car is twice the rate of the bus. The car arrives 5 hours ahead of the bus. Find the rate of the car. \n" );
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Algebra.Com's Answer #31513 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! A car and a bus leave a town at 1 pm and head for a town 300 miles away. The rate of the car is twice the rate of the bus. The car arrives 5 hours ahead of the bus. Find the rate of the car.\r \n" ); document.write( "\n" ); document.write( "Bus DATA: \n" ); document.write( "distance=300 mi; rate = x mi/hr; time=d/r = (300/x) hr.\r \n" ); document.write( "\n" ); document.write( "Car DATA: \n" ); document.write( "distance=300 mi; rate = rate = 2x mi/hr ; time = d/r = 300(2x) hr.\r \n" ); document.write( "\n" ); document.write( "EQUATIOn: \n" ); document.write( "car time = bus time - 5 hr.\r \n" ); document.write( "\n" ); document.write( "300/2x = 300/x - 5 \n" ); document.write( "Divide thru by 300 to get: \n" ); document.write( "1/2x = 1/x - 1/60 \n" ); document.write( "Multiply thru by 2x to get: \n" ); document.write( "1 = 2 - x/30 \n" ); document.write( "-1=-x/30 \n" ); document.write( "x=30 \n" ); document.write( "2x=60 mph (The rate of the car) \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |