document.write( "Question 47677This question is from textbook Introductory Algebra
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document.write( ": A car and a bus leave a town at 1 pm and head for a town 300 miles away. The rate of the car is twice the rate of the bus. The car arrives 5 hours ahead of the bus. Find the rate of the car. \n" );
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Algebra.Com's Answer #31508 by checkley71(8403)![]() ![]() ![]() You can put this solution on YOUR website! RT=R/2(T+5) OR RT=(RT+5R)/2 OR 2RT=RT+5R DIVIDING ALL TERMS BY R WE GET \r \n" ); document.write( "\n" ); document.write( "2T=T+5 OR T=5 & RT=300 OR R*5=300 OR R=300/5 OR R=60 MPH FOR THE CAR\r \n" ); document.write( "\n" ); document.write( "300/60=5 HOURS 300/30=10 HOURS THUS 10-5=5 HOURS DIFFERENCE. \n" ); document.write( " |