document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=459004>Question 459004</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Louis lives 5 miles from school and jogs at a rate of 6 mph.  Andrea lives 3.9 miles from school and jogs at a rate of 6.5 mph.  Andrea leaves her house at 7am.  When should Louis leave his house to arrive at school at the same time as Andrea? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #315036 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel1380><B>jorel1380(3719)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel1380><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=jorel1380><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=315036\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3.9 miles/6.5 mph=.6 hours<BR>\n" );
document.write( "5 miles/6 mph=.83 hours=50 mins<BR>\n" );
document.write( "Andrea arrives at school at 7:36 (7 a.m. + .6 hours), So Louis should leave 50 minutes before then, or at 6:46 a.m.. </SPAN>\n" );
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