document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=459266>Question 459266</A>: <I><SPAN STYLE=\"word-break: break-all;\"> &#8736;x and &#8736;y are complementary. If m&#8736;x = a + 3 and m&#8736;y = 2a + 6, what is the measure of &#8736;x? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #314970 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=314970\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The sum of \"complementary\" angles is 90 degrees.<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Therefore,<BR>\n" );
document.write( "(a+3) + (2a+6) = 90<BR>\n" );
document.write( "solving for 'a':<BR>\n" );
document.write( "a+3 + 2a+6 = 90<BR>\n" );
document.write( "3a+9 = 90<BR>\n" );
document.write( "3a = 81<BR>\n" );
document.write( "a = 27<BR>\n" );
document.write( ".<BR>\n" );
document.write( "since measure of angle 'a' is a+3:<BR>\n" );
document.write( "a+3 = 27+3 = 30 degrees </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );