document.write( "Question 459265: use log(4, 7)=1.4037 and log(4, 3)= 0.7925 to evaluate each expression\r
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document.write( "log(4, 9)\r
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document.write( "log(4, 7/12) \n" );
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Algebra.Com's Answer #314969 by nerdybill(7384)![]() ![]() You can put this solution on YOUR website! use log(4, 7)=1.4037 and log(4, 3)= 0.7925 to evaluate each expression \n" ); document.write( "log(4, 9) \n" ); document.write( "we can rewrite the 9 as 3^2 \n" ); document.write( "log(4, 3^2) \n" ); document.write( "2*log(4, 3) \n" ); document.write( "now we can perform the substitution: \n" ); document.write( "2*0.7925 \n" ); document.write( "1.585 \n" ); document.write( " \n" ); document.write( ".\r \n" ); document.write( "\n" ); document.write( "log(4, 7/12) \n" ); document.write( "we rewrite as: \n" ); document.write( "log(4, 7) - log(4,12) \n" ); document.write( "log(4, 7) - [log(4,4*3)] \n" ); document.write( "log(4, 7) - [log(4,4) + log(4,3)] \n" ); document.write( "log(4, 7) - [log(4,4) + log(4,3)] \n" ); document.write( "1.4037 - [1 + 0.7925] \n" ); document.write( "1.4037 - 1.7925 \n" ); document.write( "-0.3888\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |