document.write( "Question 459265: use log(4, 7)=1.4037 and log(4, 3)= 0.7925 to evaluate each expression\r
\n" ); document.write( "\n" ); document.write( "log(4, 9)\r
\n" ); document.write( "\n" ); document.write( "log(4, 7/12)
\n" ); document.write( "

Algebra.Com's Answer #314969 by nerdybill(7384)\"\" \"About 
You can put this solution on YOUR website!
use log(4, 7)=1.4037 and log(4, 3)= 0.7925 to evaluate each expression
\n" ); document.write( "log(4, 9)
\n" ); document.write( "we can rewrite the 9 as 3^2
\n" ); document.write( "log(4, 3^2)
\n" ); document.write( "2*log(4, 3)
\n" ); document.write( "now we can perform the substitution:
\n" ); document.write( "2*0.7925
\n" ); document.write( "1.585
\n" ); document.write( "
\n" ); document.write( ".\r
\n" ); document.write( "\n" ); document.write( "log(4, 7/12)
\n" ); document.write( "we rewrite as:
\n" ); document.write( "log(4, 7) - log(4,12)
\n" ); document.write( "log(4, 7) - [log(4,4*3)]
\n" ); document.write( "log(4, 7) - [log(4,4) + log(4,3)]
\n" ); document.write( "log(4, 7) - [log(4,4) + log(4,3)]
\n" ); document.write( "1.4037 - [1 + 0.7925]
\n" ); document.write( "1.4037 - 1.7925
\n" ); document.write( "-0.3888\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );