document.write( "Question 459005: Please note that graphing is not allowed in solving this.\r
\n" ); document.write( "\n" ); document.write( "If (x^2/49)+(y^2/4)=1 and x^2=7y, then what are the values of x and y? \n" ); document.write( "
Algebra.Com's Answer #314845 by lwsshak3(11628)\"\" \"About 
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Please note that graphing is not allowed in solving this.
\n" ); document.write( "If (x^2/49)+(y^2/4)=1 and x^2=7y, then what are the values of x and y
\n" ); document.write( "..
\n" ); document.write( "(x^2/49)+(y^2/4)=1
\n" ); document.write( "x^2=7y
\n" ); document.write( "..
\n" ); document.write( "7y/49)+(y^2/4)=1
\n" ); document.write( "y/7+y^2/4=1
\n" ); document.write( "4y+7y^2=28
\n" ); document.write( "7y^2+4y-28=0
\n" ); document.write( "solve by quadratic formula
\n" ); document.write( "a=7, b=4, c=-28
\n" ); document.write( "y=[-4±sqrt(4^2-4*7*-28)]2*7
\n" ); document.write( "y=[-4±√(800)]14
\n" ); document.write( "y=(-4±28.28)/14
\n" ); document.write( "y=-2.31 (reject, y≥0)
\n" ); document.write( "or
\n" ); document.write( "y=1.73
\n" ); document.write( "..
\n" ); document.write( "(x^2/49)+(y^2/4)=1
\n" ); document.write( "for y=1.73
\n" ); document.write( "(x^2/49)+(3/4)=1
\n" ); document.write( "x^2+36.75=49
\n" ); document.write( "x^2=12.25
\n" ); document.write( "x=±√12.25
\n" ); document.write( "x=±3.5
\n" ); document.write( "ans:
\n" ); document.write( "Points of intersection: (3.5,1.73) & (-3.5,1.73)
\n" ); document.write( "..
\n" ); document.write( "check:
\n" ); document.write( "(x^2/49)+(y^2/4)=1
\n" ); document.write( "3.5^2/49+1.73^2/4
\n" ); document.write( ".25+.75..=1 \n" ); document.write( "
\n" );