document.write( "Question 458999: Please note that graphing is not allowed to solve this.\r
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document.write( "If x^2+y^2=36 and (x^2/16)+(y^2/64)=1, then what are the values of x and y? \n" );
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Algebra.Com's Answer #314835 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! If x^2 + y^2 = 36 and (x^2/16)+(y^2/64)=1, then what are the values of x and y? \n" ); document.write( "Get rid of the annoying fraction in the 2nd equation \n" ); document.write( " \n" ); document.write( "multiply by 64 and we have \n" ); document.write( "4(x^2) + y^2 = 64 \n" ); document.write( ": \n" ); document.write( "Use elimination with the 1st equation just as it is \n" ); document.write( "4x^2 + y^2 = 64 \n" ); document.write( "x^2 + y^2 = 36 \n" ); document.write( "----------------subtraction eliminates y^2, find x^2 \n" ); document.write( "3x^2 = 28 \n" ); document.write( "x^2 = \n" ); document.write( "x = \n" ); document.write( ": \n" ); document.write( "Find y, replace x^2 with \n" ); document.write( " \n" ); document.write( "y^2 = 36 - \n" ); document.write( "y^2 = \n" ); document.write( "y = \n" ); document.write( "y = \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( " |