document.write( "Question 458999: Please note that graphing is not allowed to solve this.\r
\n" ); document.write( "\n" ); document.write( "If x^2+y^2=36 and (x^2/16)+(y^2/64)=1, then what are the values of x and y?
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Algebra.Com's Answer #314835 by ankor@dixie-net.com(22740)\"\" \"About 
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If x^2 + y^2 = 36 and (x^2/16)+(y^2/64)=1, then what are the values of x and y?
\n" ); document.write( "Get rid of the annoying fraction in the 2nd equation
\n" ); document.write( "\"%28x%5E2%2F16%29%2B%28y%5E2%2F64%29=1\"
\n" ); document.write( "multiply by 64 and we have
\n" ); document.write( "4(x^2) + y^2 = 64
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\n" ); document.write( "Use elimination with the 1st equation just as it is
\n" ); document.write( "4x^2 + y^2 = 64
\n" ); document.write( "x^2 + y^2 = 36
\n" ); document.write( "----------------subtraction eliminates y^2, find x^2
\n" ); document.write( "3x^2 = 28
\n" ); document.write( "x^2 = \"28%2F3\"
\n" ); document.write( "x = \"sqrt%2828%2F3%29\" = \"2sqrt%287%2F3%29\"
\n" ); document.write( ":
\n" ); document.write( "Find y, replace x^2 with \"28%2F3\" in the 1st equation
\n" ); document.write( "\"28%2F3\" + y^2 = 36
\n" ); document.write( "y^2 = 36 - \"28%2F3\"
\n" ); document.write( "y^2 = \"108%2F3\" - \"28%2F3\"
\n" ); document.write( "y = \"80%2F3\"
\n" ); document.write( "y = \"sqrt%2880%2F3%29\" = \"4sqrt%285%2F3%29\"
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