document.write( "Question 458524: Bicyclists Andrew and Mark started at noon from points 60 km apart and rode towards each other meeting at 1:30 pm. Andrew's speed was 4km/h greater than Mark's speed. Find their speeds.\r
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document.write( "If a driver leaves now and drives 66km/h, he will reach town A just in time. On the other hand, if he has lunch first and leaves in 40 min, he will have to drive at 90 km/h to make it on time. How far is the town A? \n" );
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Algebra.Com's Answer #314816 by jorel1380(3719)![]() ![]() You can put this solution on YOUR website! 3/2(x+x+4)=60 \n" ); document.write( "3(2x+4)=120 \n" ); document.write( "2x+4=40 \n" ); document.write( "2x=36 \n" ); document.write( "x=18 \n" ); document.write( "Mark rode at 18 kph, and Andrew rode at 22 kph \n" ); document.write( "--------------------------------- \n" ); document.write( "x/66=x/90+2/3 \n" ); document.write( "x/22=x/30+2 \n" ); document.write( "30x=22x+1320 \n" ); document.write( "8x=1320 \n" ); document.write( "x=165 kilometers \n" ); document.write( "165/66=2.5 \n" ); document.write( "165/90+2/3=165/90+60/90=225/90=2.5 \n" ); document.write( " |