document.write( "Question 47662This question is from textbook College Algebra
\n" ); document.write( ": Which of the given interest rates and compounding periods would provide the better investment?
\n" ); document.write( "(a) 9 1/4% per year, compounded semiannually
\n" ); document.write( "(b) 9% per year, compounded continously\r
\n" ); document.write( "\n" ); document.write( "Thank you
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Algebra.Com's Answer #31480 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
Consider the result after one year (t=1)\r
\n" ); document.write( "\n" ); document.write( "(a) 9 1/4% per year, compounded semiannually\r
\n" ); document.write( "\n" ); document.write( "A=P(1+0.0925/(2t)^(2t)
\n" ); document.write( "A=P(1+0.04625)^2
\n" ); document.write( "A=P(1.09463906...\r
\n" ); document.write( "\n" ); document.write( "(b) 9% per year, compounded continously
\n" ); document.write( "A=Pe^(0.09t)
\n" ); document.write( "A=Pe^0.09
\n" ); document.write( "A=P(1.09417428...)\r
\n" ); document.write( "\n" ); document.write( "So,for one year the 9 % compounded continuously is growing faster.\r
\n" ); document.write( "\n" ); document.write( "You would have to look at other values of t (maybe by graphing)
\n" ); document.write( "to see which is better in the long run. I suspect the
\n" ); document.write( "continuous compounding would be the winner.
\n" ); document.write( "To do this, let P be $1.00 and let t=x.\r
\n" ); document.write( "\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.\r
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