document.write( "Question 47662This question is from textbook College Algebra
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document.write( ": Which of the given interest rates and compounding periods would provide the better investment?
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document.write( "(a) 9 1/4% per year, compounded semiannually
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document.write( "(b) 9% per year, compounded continously\r
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document.write( "Thank you \n" );
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Algebra.Com's Answer #31480 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Consider the result after one year (t=1)\r \n" ); document.write( "\n" ); document.write( "(a) 9 1/4% per year, compounded semiannually\r \n" ); document.write( "\n" ); document.write( "A=P(1+0.0925/(2t)^(2t) \n" ); document.write( "A=P(1+0.04625)^2 \n" ); document.write( "A=P(1.09463906...\r \n" ); document.write( "\n" ); document.write( "(b) 9% per year, compounded continously \n" ); document.write( "A=Pe^(0.09t) \n" ); document.write( "A=Pe^0.09 \n" ); document.write( "A=P(1.09417428...)\r \n" ); document.write( "\n" ); document.write( "So,for one year the 9 % compounded continuously is growing faster.\r \n" ); document.write( "\n" ); document.write( "You would have to look at other values of t (maybe by graphing) \n" ); document.write( "to see which is better in the long run. I suspect the \n" ); document.write( "continuous compounding would be the winner. \n" ); document.write( "To do this, let P be $1.00 and let t=x.\r \n" ); document.write( "\n" ); document.write( "Cheers, \n" ); document.write( "Stan H.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |