document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=458930>Question 458930</A>: <I><SPAN STYLE=\"word-break: break-all;\"> When you have an equation that is log8 4 + log8 16 and you have to solve in a single logarithim form. isnt just 4 * 16? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #314795 by </B><A HREF=/tutors/aboutme.mpl?userid=math-vortex><B>math-vortex(648)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=math-vortex><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=math-vortex><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=314795\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Good thinking! Yes, when both logarithms have the same base, you use the product rule. So,\r<BR>\n" );
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document.write( "log[8] 4 + log[8] 16 = log[8] 64 because 4x16=64. </SPAN>\n" );
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