document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=458931>Question 458931</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how many gallons of 70% anifreeze solution must be mixed with 70 gallons of 15% antifreeze to get a mixture that is 60% antifreeze?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #314794 by </B><A HREF=/tutors/aboutme.mpl?userid=htmentor><B>htmentor(1343)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=htmentor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=htmentor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=314794\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> how many gallons of 70% anifreeze solution must be mixed with 70 gallons of 15% antifreeze to get a mixture that is 60% antifreeze?<BR>\n" );
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document.write( "Let x = the number of gallons of 70% antifreeze solution<BR>\n" );
document.write( "Then the number of gallons of antifreeze making up the mixture will be:<BR>\n" );
document.write( "0.7x + 0.15*70 = 0.6*(x+70)<BR>\n" );
document.write( "0.7x + 10.5 = 0.6x + 42<BR>\n" );
document.write( "Solve for x:<BR>\n" );
document.write( "0.1x = 31.5<BR>\n" );
document.write( "x = 315<BR>\n" );
document.write( "So, we need 315 gallons of 70% antifreeze solution<BR>\n" );
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