document.write( "Question 458829: 4*5^n=4*125
\n" ); document.write( "20^n=500
\n" ); document.write( "500/20=25
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Algebra.Com's Answer #314736 by Gladiola(1)\"\" \"About 
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4*5^n=4*125
\n" ); document.write( "20^n=500
\n" ); document.write( "500/20=25\r
\n" ); document.write( "\n" ); document.write( "First you do 4*20 wich equals 20 then you do 4*125 wich equals 500
\n" ); document.write( "and you get 25
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