document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=458823>Question 458823</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the sum of two angle is 130. if the larger is 10 more than twice the smaller find the 2 angle<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #314728 by </B><A HREF=/tutors/aboutme.mpl?userid=simranb><B>simranb(63)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=simranb><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=simranb><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=314728\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the smaller angle be x<BR>\n" );
document.write( "then larger angle=2x+10<BR>\n" );
document.write( "their sum=130<BR>\n" );
document.write( "so<BR>\n" );
document.write( "x+2x+10=130<BR>\n" );
document.write( "3x+10=130<BR>\n" );
document.write( "3x=130-10<BR>\n" );
document.write( "3x=120<BR>\n" );
document.write( "x=120/3<BR>\n" );
document.write( "x=40<BR>\n" );
document.write( "then 2x+10=2*40+10<BR>\n" );
document.write( "          =80+10=90<BR>\n" );
document.write( "so the two angles are 90 and 40<BR>\n" );
document.write( "Hope this helps! </SPAN>\n" );
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