document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=458816>Question 458816</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How much water needs to be added to a half ounce of a solution in which the active ingredient is 10% so as to make that half ounce of solution into having .5% of the active ingredient? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #314725 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=314725\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> How much water needs to be added to a half ounce of a solution in which the active ingredient is 10% so as to make that half ounce of solution into having .5% of the active ingredient?<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "active + active = active<BR>\n" );
document.write( "0.10*(1/2) + 0*x = 0.005((1/2)+x))<BR>\n" );
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document.write( "Multiply thru by 1000 to get:<BR>\n" );
document.write( "50 + 0 = (5/2) + 5x<BR>\n" );
document.write( "5x = 47.5<BR>\n" );
document.write( "x = 9.5 ounces (amt of water needed)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );