document.write( "Question 458794: how do you find the y-coordinate of the point of intersection for the two lines below?\r
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document.write( "-6x+7y=20
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document.write( "2x-3y=4\r
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document.write( "how do you find the x-coordinate of the point of intersection for the two lines below?\r
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document.write( "x-2y=-2
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document.write( "y=-6x+40 \n" );
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Algebra.Com's Answer #314721 by amoresroy(361)![]() ![]() You can put this solution on YOUR website! how do you find the y-coordinate of the point of intersection for the two lines below?\r \n" ); document.write( "\n" ); document.write( "-6x+7y=20 \n" ); document.write( "2x-3y=4\r \n" ); document.write( "\n" ); document.write( "Multiply the 2nd equation by 3 to get \n" ); document.write( "6x-9y=12\r \n" ); document.write( "\n" ); document.write( "Add the 2 equations to eliminate x \n" ); document.write( "7y-9y=32 \n" ); document.write( "-2y = 32 \n" ); document.write( "y = -16\r \n" ); document.write( "\n" ); document.write( "The y-coordinate is -16 \n" ); document.write( "----------------------------------------------\r \n" ); document.write( "\n" ); document.write( "how do you find the x-coordinate of the point of intersection for the two lines below?\r \n" ); document.write( "\n" ); document.write( "x-2y=-2 \n" ); document.write( "y=-6x+40 \n" ); document.write( "Rearrange 2nd equation to get \n" ); document.write( "6x+y=40\r \n" ); document.write( "\n" ); document.write( "Multiply the 1st equation by 6 to get \n" ); document.write( "6x-12y=-12\r \n" ); document.write( "\n" ); document.write( "Subtract above equation from 2nd equation \n" ); document.write( "(6x-6x)+(y- -12y) = 40 - -12 \n" ); document.write( "13y = 52 \n" ); document.write( "y = 4 \n" ); document.write( " Substitute y =4 in 1st equation to solve for x \n" ); document.write( "x-2(4) = -2 \n" ); document.write( "x = 6\r \n" ); document.write( "\n" ); document.write( "The x-coordinate of the point of intersection for the two lines is 6. \n" ); document.write( " |