document.write( "Question 458796: please help me solve this problem. a person wishes to invest $20.000 int two enterprises so total income per year will be $1440. one enterprise pay 6% annualy, the other has more risk and pays 7,5% annualy. how much must be invested in each? \n" ); document.write( "
Algebra.Com's Answer #314720 by amoresroy(361)\"\" \"About 
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Let x = investment at 6% annually
\n" ); document.write( " 20,000- x = investment at 7.5% annually\r
\n" ); document.write( "\n" ); document.write( "Equation:
\n" ); document.write( ".06x + .075(20,000-x) = 1440
\n" ); document.write( ".06x + 1500 -.075x = 1440
\n" ); document.write( ".015x = 60
\n" ); document.write( "x = 4000
\n" ); document.write( "20,000 - x = 16,000\r
\n" ); document.write( "\n" ); document.write( "$4,000 must be invested at 6% and $16,000 must be invested at 7.5%\r
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