document.write( "Question 458635: Write an equation for the parabola with focus (4,0) and directrix y=2.\r
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Algebra.Com's Answer #314715 by lwsshak3(11628)\"\" \"About 
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Write an equation for the parabola with focus (4,0) and directrix y=2.
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\n" ); document.write( "Standard form of parabola: (x-h)^2=4p(y-k), with (h,k) being the (x,y) coordinates of the vertex
\n" ); document.write( "Given parabola opens downward with axis of symmetry at x=4. Vertex at (4,1). p=1
\n" ); document.write( "Equation of parabola:
\n" ); document.write( "(x-4)^2=-4(y-1) (ans)
\n" ); document.write( "see the graph below as a visual check on the answer
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\n" ); document.write( "y=1-(x-4)^2/4\r
\n" ); document.write( "\n" ); document.write( "\"+graph%28+300%2C+300%2C+-10%2C+10%2C+-10%2C+10%2C+1-%28x-4%29%5E2%2F4%29+\"
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