document.write( "Question 458709: Use the Rational Root Theorem to list all possible rational roots for each equation. Then find any actual roots.\r
\n" ); document.write( "\n" ); document.write( "x^3+2x^2+3x+6=0
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Algebra.Com's Answer #314694 by robertb(5830)\"\" \"About 
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Applying the rational root theorem, possible rational roots are -6, -3,-2, -1, 1,2,3,6.
\n" ); document.write( "Using the remainder theorem (or synthetic division), trying out x = -2:\r
\n" ); document.write( "\n" ); document.write( "\"%28-2%29%5E3+%2B+2%28-2%29%5E2+%2B+3%28-2%29+%2B+6+=+0\" Hence x = -2 is a rational root. After synthetic division, the quotient is \"x%5E2+%2B+3\", which doesn't even have real roots.
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