document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=458764>Question 458764</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How many milliliters of pure acid must be added to 150 milliliters of a 70% solution of acid to obtain a 80% solution?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #314693 by </B><A HREF=/tutors/aboutme.mpl?userid=robertb><B>robertb(5830)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=robertb><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=robertb><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=314693\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 150*0.70 + x*1.00 = (150+x)*0.80\r<BR>\n" );
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document.write( "==> 105 + x = 120 + 0.80x\r<BR>\n" );
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document.write( "==> x - 0.80x = 120 - 105\r<BR>\n" );
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document.write( "==> 0.20x = 15\r<BR>\n" );
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document.write( "==> x = 75 milliliters of pure acid must be added. </SPAN>\n" );
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