document.write( "Question 458756: I wasn't sure where to put this.\r
\n" ); document.write( "\n" ); document.write( "Consider only the discriminant, b^2-4ac, to determine whether one real-number solutions, or two different imaginary-number solutions exist.\r
\n" ); document.write( "\n" ); document.write( "x^2+3x+7=0\r
\n" ); document.write( "\n" ); document.write( "thanks for the help. \n" ); document.write( "

Algebra.Com's Answer #314690 by math-vortex(648) $\"\"$ $\"About$

You can put this solution on YOUR website!
Begin by determining a, b, and c in your equation. The standard form for a quadratic equation is $\"ax%5E2%2Bbx%2Bc=0\"$ . \r
\n" ); document.write( "\n" ); document.write( "In your equation, a=1, b=3, and c=7. Evaluate $\"b%5E2-4ac\"$ using these values for a, b, and c. So, $\"b%5E2-4ac=%283%29%5E2-4%281%29%287%29=9-28=-18\"$ \r
\n" ); document.write( "\n" ); document.write( "Important Math Fact:
\n" ); document.write( "If $\"b%5E2-4ac%3C0\"$ (negative), then there are two imaginary-number solutions.
\n" ); document.write( "If $\"b%5E2-4ac%3E0\"$ (positive), then there are two real-number solutions.
\n" ); document.write( "If $\"b%5E2-4ac=0\"$ , then there is one real-number solution.\r
\n" ); document.write( "\n" ); document.write( "Your discriminant is negative, so you have two non-real (imaginary number) solutions.\r
\n" ); document.write( "\n" ); document.write( "*******
\n" ); document.write( "NOTE:
\n" ); document.write( "If you forget this math fact, think about the quadratic formula $\"x=%28b%2B-+sqrt%28b%5E2-4ac%29%29%2F2a\"$ .\r
\n" ); document.write( "\n" ); document.write( "If the value under the square root is negative, then the solution cannot be a real number. If the value under the square root is positive, \"+\" or \"-\" after \"-b\" gives us two real number solutions. If the number under the square root is zero, then we just get one real-number solution, because the square root of zero is zero. \n" ); document.write( "

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