document.write( "Question 458699: In still water, a boat averages 30 miles per hour. It takes the boat the same amount of time to travel 16 mles downstream, with the current, as 14 miles upstream, against the current. What is the rate of the water's current? \n" ); document.write( "
Algebra.Com's Answer #314660 by mananth(16949) You can put this solution on YOUR website! Boat speed = 30 mph \n" ); document.write( "current speed = x mph \n" ); document.write( "wind speed \n" ); document.write( "speed against current 30 - x \n" ); document.write( "speed with current 30 + x \n" ); document.write( " \n" ); document.write( "Distance against wind 14 miles \n" ); document.write( "Distance with wind 16 miles \n" ); document.write( " \n" ); document.write( "t=d/r time against = time with \n" ); document.write( "14/(30-x )=16/(30 +x) \n" ); document.write( "14(30+x )=16(30-x) \n" ); document.write( "420+14x =480-16x \n" ); document.write( "16x+14x =60 \n" ); document.write( "30x=60 \n" ); document.write( "/30 \n" ); document.write( "x=2 mph current speed \n" ); document.write( " \n" ); document.write( " |