document.write( "Question 458667: What equation describes the line that contains the points (7,17) and 15,33)? \n" ); document.write( "
Algebra.Com's Answer #314615 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "First let's find the slope of the line through the points and \r
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\n" ); document.write( "\n" ); document.write( "Note: is the first point . So this means that \"x%5B1%5D=7\" and \"y%5B1%5D=17\".\r
\n" ); document.write( "\n" ); document.write( "Also, is the second point . So this means that \"x%5B2%5D=15\" and \"y%5B2%5D=33\".\r
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\n" ); document.write( "\n" ); document.write( "\"m=%28y%5B2%5D-y%5B1%5D%29%2F%28x%5B2%5D-x%5B1%5D%29\" Start with the slope formula.\r
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\n" ); document.write( "\n" ); document.write( "\"m=%2833-17%29%2F%2815-7%29\" Plug in \"y%5B2%5D=33\", \"y%5B1%5D=17\", \"x%5B2%5D=15\", and \"x%5B1%5D=7\"\r
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\n" ); document.write( "\n" ); document.write( "\"m=%2816%29%2F%2815-7%29\" Subtract \"17\" from \"33\" to get \"16\"\r
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\n" ); document.write( "\n" ); document.write( "\"m=%2816%29%2F%288%29\" Subtract \"7\" from \"15\" to get \"8\"\r
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\n" ); document.write( "\n" ); document.write( "\"m=2\" Reduce\r
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\n" ); document.write( "\n" ); document.write( "So the slope of the line that goes through the points and is \"m=2\"\r
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\n" ); document.write( "\n" ); document.write( "Now let's use the point slope formula:\r
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\n" ); document.write( "\n" ); document.write( "\"y-y%5B1%5D=m%28x-x%5B1%5D%29\" Start with the point slope formula\r
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\n" ); document.write( "\n" ); document.write( "\"y-17=2%28x-7%29\" Plug in \"m=2\", \"x%5B1%5D=7\", and \"y%5B1%5D=17\"\r
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\n" ); document.write( "\n" ); document.write( "\"y-17=2x%2B2%28-7%29\" Distribute\r
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\n" ); document.write( "\n" ); document.write( "\"y-17=2x-14\" Multiply\r
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\n" ); document.write( "\n" ); document.write( "\"y=2x-14%2B17\" Add 17 to both sides. \r
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\n" ); document.write( "\n" ); document.write( "\"y=2x%2B3\" Combine like terms. \r
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\n" ); document.write( "\n" ); document.write( "So the equation that goes through the points and is \"y=2x%2B3\"\r
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