document.write( "Question 458657: hi im not really sure if my question would be in this category but if you could help me the best way you can that would mean a lot to me thanks\r
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document.write( "[3x-2/2x^2-5x-3]-[1/x-3]\r
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document.write( "can you please walk me through this im clueless \n" );
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Algebra.Com's Answer #314611 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! [3x-2/2x^2-5x-3]-[1/x-3] \n" ); document.write( " \n" ); document.write( "---- \n" ); document.write( "Factor where you can: \n" ); document.write( "= [3x-2/(x-3)(2x+1)]-[1/x-3] \n" ); document.write( "------- \n" ); document.write( "Least common denominator: (x-3)(2x+1) \n" ); document.write( "----------- \n" ); document.write( "Rewrite each fraction with the lcd as its denominator: \n" ); document.write( "= [(3x-2)/lcd] - [(2x+1)/lcd] \n" ); document.write( "----------- \n" ); document.write( "Combine the numerators over the lcd: \n" ); document.write( "= [3x-2-2x-1]/lcd \n" ); document.write( "--- \n" ); document.write( "= (x-3)/[(x-3)(2x+1)] \n" ); document.write( "---- \n" ); document.write( "Cancel the common (x-3) factor to get: \n" ); document.write( "---- \n" ); document.write( "= 1/(2x+1) \n" ); document.write( "=================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |