document.write( "Question 47624: Swimming pool design. An architect has designed a motel pool within a rectangular area that is fenced on three sides (the 4th side is framed by a building). If she uses 60 yards of fencing to enclose an area of 352 square yards, then what are the dimensions of the two lengths and one width? Assume L is greater than W. \n" ); document.write( "
Algebra.Com's Answer #31460 by Nate(3500)\"\" \"About 
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There are two lengths and one width:
\n" ); document.write( "\"2l+%2B+w+=+60\"
\n" ); document.write( "Area:
\n" ); document.write( "\"lw+=+352\"
\n" ); document.write( "Combine using \"w+=+60+-+2l\":
\n" ); document.write( "\"l%2860+-+2l%29+=+352\"
\n" ); document.write( "\"-2l%5E2+%2B+60l+-+352+=+0\"
\n" ); document.write( "\"l%5E2+-+30l+%2B+176+=+0\"
\n" ); document.write( "\"%28l+-+8%29%28l+-+22%29+=+0\"
\n" ); document.write( "l = 8 or l = 22
\n" ); document.write( "When you think, the length is longer than the width, so the length can not be eight yards.
\n" ); document.write( "l = 22
\n" ); document.write( "plug:
\n" ); document.write( "\"2l+%2B+w+=+60\"
\n" ); document.write( "\"44+%2B+w+=+60\"
\n" ); document.write( "\"w+=+16\"
\n" ); document.write( "22 yards x 16 yards
\n" ); document.write( "
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