document.write( "Question 458539: 3^(x2-12) = 9^(2x) someone PLZ help Im stuck on this ONE question!!! \n" ); document.write( "
Algebra.Com's Answer #314558 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!
\"3%5E%28x%5E2-12%29+=+9%5E%282x%29\"...write \"9\" as \"3%5E2\" \r
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\n" ); document.write( "\n" ); document.write( "\"3%5E%28x%5E2-12%29+=+3%5E2%282x%29+\"\r
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\n" ); document.write( "\n" ); document.write( "\"3%5E%28x%5E2-12%29+=+3%5E%284x%29+\"........if bases are same then exponents are same too\r
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\n" ); document.write( "\n" ); document.write( "so, you have:\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2-12=4x\".......solve for \"x\"\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2-4x-12=0\"..replace \"-4x\" with \"-6x%2B2x\"
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\n" ); document.write( "\n" ); document.write( "\"x%5E2-6x%2B2x-12=0\".....group\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%5E2-6x%29%2B%282x-12%29=0\"\r
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\n" ); document.write( "\n" ); document.write( "\"x%28x-6%29%2B2%28x-6%29=0\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%2B2%29%28x-6%29=0\"\r
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\n" ); document.write( "\n" ); document.write( "solutions:\r
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\n" ); document.write( "\n" ); document.write( "\"x%2B2=0\".........->....\"x=-2\"\r
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\n" ); document.write( "\n" ); document.write( "\"x-6=0\".......->....\"x=6\"\r
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