document.write( "Question 458534: I have to evaluate the discriminate of each equation. Tell how many solutions each equation has and whether the solutions are real or imaginary.\r
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Algebra.Com's Answer #314556 by Edwin McCravy(20059)\"\" \"About 
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document.write( "Rule:\r\n" );
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document.write( "Ax² + Bx + C = 0\r\n" );
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document.write( "1. Substitute A, B, and C in the discriminant formula\r\n" );
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document.write( "       Discriminant = B² - 4AC\r\n" );
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document.write( "2. If the discriminant is a positive number then the equation\r\n" );
document.write( "   has two real solutions.\r\n" );
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document.write( "3. If the discriminant is a negative number then the equation\r\n" );
document.write( "   has two conjugate imaginary solutions.\r\n" );
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document.write( "4. If the discriminant is zero then the equation\r\n" );
document.write( "   has one real solution.\r\n" );
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document.write( "x² - 4x - 5 = 0\r\n" );
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document.write( "A = 1, B = -4, C = -5\r\n" );
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document.write( "Substitute A=1, B=-4, and C=-5 in the discriminant formula\r\n" );
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document.write( "       Discriminant = B² - 4AC\r\n" );
document.write( "       Discriminant = (-4)² - 4(1)(-5)\r\n" );
document.write( "       Discriminant = 16 + 20\r\n" );
document.write( "       Discriminant = 36\r\n" );
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document.write( "36 is a negative number, so the equation has two real \r\n" );
document.write( "solutions.\r\n" );
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document.write( "x² - 12x + 36 = 0\r\n" );
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document.write( "A = 1, B = -12, C = 36\r\n" );
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document.write( "Substitute A=1, B=-12, and C=36 in the discriminant formula\r\n" );
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document.write( "       Discriminant = B² - 4AC\r\n" );
document.write( "       Discriminant = (-12)² - 4(1)(36)\r\n" );
document.write( "       Discriminant = 144 - 144\r\n" );
document.write( "       Discriminant = 0\r\n" );
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document.write( "That came out zero, so the equation has one \r\n" );
document.write( "real solutions.\r\n" );
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document.write( "Edwin
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