document.write( "Question 458533: I have to evaluate the discriminate of each equation. Tell how many solutions each equation has and whether the solutions are real or imaginary.\r
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Algebra.Com's Answer #314553 by Edwin McCravy(20056)\"\" \"About 
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document.write( "Rule:\r\n" );
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document.write( "Ax² + Bx + C = 0\r\n" );
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document.write( "1. Substitute A, B, and C in the discriminant formula\r\n" );
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document.write( "       Discriminant = B² - 4AC\r\n" );
document.write( "2. If the discriminant is a positive number then the equation\r\n" );
document.write( "   has two real solutions.\r\n" );
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document.write( "3. If the discriminant is a negative number then the equation\r\n" );
document.write( "   has two conjugate imaginary solutions.\r\n" );
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document.write( "4. If the discriminant is zero then the equation\r\n" );
document.write( "   has one real solution.\r\n" );
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document.write( "2x² + x + 28 = 0\r\n" );
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document.write( "A = 2, B = 1, C = 28\r\n" );
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document.write( "Substitute A=2, B=1, and C=28 in the discriminant formula\r\n" );
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document.write( "       Discriminant = B² - 4AC\r\n" );
document.write( "       Discriminant = 1² - 4(2)(28)\r\n" );
document.write( "       Discriminant = 1 - 224\r\n" );
document.write( "       Discriminant = -223\r\n" );
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document.write( "-223 is a negative number, so the equation has two \r\n" );
document.write( "conjugate imaginary solutions.\r\n" );
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document.write( "-----------------------------\r\n" );
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document.write( "6x² - 2x + 5 = 0\r\n" );
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document.write( "A = 6, B = -2, C = 5\r\n" );
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document.write( "Substitute A=6, B=-2, and C=5 in the discriminant formula\r\n" );
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document.write( "       Discriminant = B² - 4AC\r\n" );
document.write( "       Discriminant = (-2)² - 4(6)(5)\r\n" );
document.write( "       Discriminant = 4 - 120\r\n" );
document.write( "       Discriminant = -116\r\n" );
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document.write( "-116 is a negative number, so the equation has two \r\n" );
document.write( "conjugate imaginary solutions.\r\n" );
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document.write( "Edwin
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