document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=458488>Question 458488</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The area of a square is 5  more than its perimeter. find the length of a side ? how would i solve this  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #314551 by </B><A HREF=/tutors/aboutme.mpl?userid=richard1234><B>richard1234(7193)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richard1234><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richard1234><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=314551\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If the area of the square is *numerically* five more than its perimeter, then we would say that\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE A = P + 5\">\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE s^2 = 4s + 5\">\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE s^2 - 4s - 5 = 0 \Rightarrow (s - 5)(s + 1) = 0 \Rightarrow s = 5\"> (discard the negative solution -1). </SPAN>\n" );
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