document.write( "Question 458330: Solve: log base7(2x+9) = log base7x+log base7(x+10) \n" ); document.write( "
Algebra.Com's Answer #314547 by lwsshak3(11628)\"\" \"About 
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Solve: log base7(2x+9) = log base7x+log base7(x+10)
\n" ); document.write( "..
\n" ); document.write( "log7(2x+9)=log7(x)+log7(x+10)
\n" ); document.write( "log7(2x+9)-(log7(x)+log7(x+10)=0
\n" ); document.write( "place under single log
\n" ); document.write( "log7[(2x+9)/(x)(x+10)=0
\n" ); document.write( "log7[(2x+9)/(x^2+10x)]=0
\n" ); document.write( "convert to exponential form: (base(7) raised to log of number(0)=number[(2x+9)/(x^2+10x)]
\n" ); document.write( "7^0=[(2x+9)/(x^2+10x)]=1
\n" ); document.write( "2x+9=x^2+10x
\n" ); document.write( "x^2+8x-9=0
\n" ); document.write( "(x+9)(x-1)=0
\n" ); document.write( "x=-9 (reject, x>0)
\n" ); document.write( "or
\n" ); document.write( "x=1 (ans) \n" ); document.write( "
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