document.write( "Question 458433: Factor the expression:
\n" ); document.write( "(x-1)^3+1\r
\n" ); document.write( "\n" ); document.write( "This is as far as I got:
\n" ); document.write( "(x-1) (x-1) (x-1)+1
\n" ); document.write( "Then I tried to factor by grouping the four terms
\n" ); document.write( "x-1(1) 1(x-1)\r
\n" ); document.write( "\n" ); document.write( "I'm lost.
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Algebra.Com's Answer #314523 by Alan3354(69443)\"\" \"About 
You can put this solution on YOUR website!
Factor the expression:
\n" ); document.write( "(x-1)^3+1
\n" ); document.write( "---------
\n" ); document.write( "It's the sum of 2 cubes.
\n" ); document.write( "Sub y for x-1
\n" ); document.write( "-------
\n" ); document.write( "\"y%5E3+%2B+1+=+%28y%2B1%29%2A%28y%5E2+-+y+%2B+1%29\"
\n" ); document.write( "then sub x-1 for y
\n" ); document.write( "= \"x%2A%28%28x-1%29%5E2+-+%28x-1%29+%2B+1%29\"
\n" ); document.write( "= \"x%2A%28x%5E2+-+3x+%2B+3%29\"
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