document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=47618>Question 47618</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 1.) y=-2/3x+4 by graphing 3 points </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #31452 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=31452\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> SETTING Y=0 WE GET 0=-2/3X+4 OR -4=-2/3X OR -12=-2X OR X=6 THUS ONE POINT IS (6,0)\r<BR>\n" );
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document.write( "SETTING X=12 WE GET Y=-2/3(12)+4 OR Y=-8+4 OR Y=-4 THUS ANOTHER POINT IS<BR>\n" );
document.write( "(12,-4)\r<BR>\n" );
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document.write( "SETTING Y=2 THEN 2=-2/3X+4 OR -2=-2/3X OR -6=-2X OR X=3 THUS ANOTHER POINT IS<BR>\n" );
document.write( "(3,2) </SPAN>\n" );
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