document.write( "Question 458426: Suppose the distribution of the diameter (in cm) of oranges from a tree is N(10,2^2) ..
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document.write( "a. Sketch a graph of the distribution that displays both the actual diameters as well as the z-score along the horizontal axis.
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document.write( "b. Find the z-score for each of the following diameters :
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document.write( "a) 12 cm b)9 mm c)13 cm
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document.write( "c. Oranges are to be dumped if their diameters have a z-score of less than -2.
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document.write( "what is the diameter of oranges that are to be dumped?
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document.write( "d If there are 120 oranges on the tree how many will be dumped?\r
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Algebra.Com's Answer #314508 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Suppose the distribution of the diameter (in cm) of oranges from a tree is \n" ); document.write( "N(10,2^2) .. \n" ); document.write( "-------------------- \n" ); document.write( "a. Sketch a graph of the distribution that displays both the actual diameters as well as the z-score along the horizontal axis. \n" ); document.write( "----- \n" ); document.write( "b. Find the z-score for each of the following diameters : \n" ); document.write( "a)12 cm::: z = (12-10)/4 = 1/2 \n" ); document.write( "b)9 mm ::: z = (9-10)/4 = -1/4 \n" ); document.write( "c)13 cm::: z = (13-10)/4 = 3/4 \n" ); document.write( "---------------------------------------------- \n" ); document.write( "Note: If the 9mm is really 9mm and not a typo, \n" ); document.write( "9/1000 = 90/100 = 90cm \n" ); document.write( "In which case the z-value is (90-10)/4 = 80/4 = 20 \n" ); document.write( "c. Oranges are to be dumped if their diameters have a z-score of less than -2. \n" ); document.write( "what is the diameter of oranges that are to be dumped? \n" ); document.write( "Use x = zs+u \n" ); document.write( "x = -2*4+10 = 2 inches \n" ); document.write( "---------------------------------- \n" ); document.write( "d If there are 120 oranges on the tree how many will be dumped? \n" ); document.write( "P(z < -2) = normalcdf(-100,-2) = 0.02275 \n" ); document.write( "# to be dumped = 0.02275*120 = 2.73 ~ 3 when rounded up \n" ); document.write( "========================================================= \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |