document.write( "Question 458332: Biting an unpopped kernel of popcorn hurts! As an experiment, a self-confessed connoisseur of cheap popcorn carefully counted 773 kernels and put them in a popper. After popping, the unpopped kernels were counted. There were 86.
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document.write( "(a) Construct a 90 percent confidence interval of the proportion of all kernels that would not pop.
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document.write( "(b) Check the normality assumption.
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document.write( "(c) Try the Very Quick Rule. Does it work well here? Why or why not?
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document.write( "(d) Why might this sample not be typical?
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Algebra.Com's Answer #314486 by edjones(8007)![]() ![]() You can put this solution on YOUR website! From yahoo.com \n" ); document.write( "Best Answer - Chosen by Asker\r \n" ); document.write( "\n" ); document.write( "We know N, the sample size, from the problem: N = 773 \n" ); document.write( "From your problem's givens, we can get p and q:\r \n" ); document.write( "\n" ); document.write( "p = 86/773 = 0.1113 \n" ); document.write( "q = 1 - p = 0.8887\r \n" ); document.write( "\n" ); document.write( "From a z table, the value for the 90% interval is:\r \n" ); document.write( "\n" ); document.write( "1.6449\r \n" ); document.write( "\n" ); document.write( "Use the formula for the interval around a proportion:\r \n" ); document.write( "\n" ); document.write( "p - z*sqrt(pq/N) to p + z*sqrt(pq/N)\r \n" ); document.write( "\n" ); document.write( "0.1113 - 1.6449*sqrt(0.1113*0.8887/773) to 0.1113 + 1.6449*sqrt(0.1113*0.8887/773)\r \n" ); document.write( "\n" ); document.write( "0.09269 to 0.12991\r \n" ); document.write( "\n" ); document.write( "No, the very quick rule won't work here, since the p value is very small.\r \n" ); document.write( "\n" ); document.write( "Yes, normality will hold, since Np and Nq are both large (86 and 687).\r \n" ); document.write( "\n" ); document.write( "This sample might not be typical, for example, since the person is a \"self-confessed connoisseur of cheap popcorn\", he might be better at making the popcorn than other people, so he might have a lower number of unpopped kernals than a normal eater. \n" ); document.write( "3 years ago \n" ); document.write( " |