document.write( "Question 458405: If \"a%5Em%2Aa%5En=a%5Emn\",then m(n-2)+n(m-2)is?options are (a)-1,(b)1 (c)0 (d)1/2 \n" ); document.write( "
Algebra.Com's Answer #314465 by jim_thompson5910(35256)\"\" \"About 
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Use the idea that \"x%5E%28y%29%2Ax%5E%28z%29=x%5E%28y%2Bz%29\" to state that \"a%5Em%2Aa%5En=a%5Emn\" is also the same as \"a%5E%28m%2Bn%29=a%5Emn\"\r
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\n" ); document.write( "\n" ); document.write( "Now, if the bases are equal, then the exponents are equal. So \"m%2Bn=mn\" or \"mn=m%2Bn\"\r
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\n" ); document.write( "\n" ); document.write( "Now all we need to do is start with m(n-2)+n(m-2) and simplify\r
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\n" ); document.write( "\n" ); document.write( "m(n-2)+n(m-2)\r
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\n" ); document.write( "\n" ); document.write( "mn-2m+nm-2n \r
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\n" ); document.write( "\n" ); document.write( "mn-2m+mn-2n \r
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\n" ); document.write( "\n" ); document.write( "mn+mn-2m-2n \r
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\n" ); document.write( "\n" ); document.write( "2mn-2(m+n)\r
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\n" ); document.write( "\n" ); document.write( "2(m+n)-2(m+n) .... Note: I've replaced mn with m+n (since \"mn=m%2Bn\")\r
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\n" ); document.write( "\n" ); document.write( "So all this shows us that m(n-2)+n(m-2) = 0 when m+n = mn\r
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\n" ); document.write( "\n" ); document.write( "Consequently, this means that m(n-2)+n(m-2) = 0 if \"a%5Em%2Aa%5En=a%5Emn\"\r
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\n" ); document.write( "\n" ); document.write( "So the answer is choice C)
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