document.write( "Question 458397: Can anyone please help me with this problem?
\n" ); document.write( "\"2log+y%2B2=logy%2B2-log12\"
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Algebra.Com's Answer #314463 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
2log y+2 = logy+2-log12
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\n" ); document.write( "2log(y) + 2 = log(y)+2 - log(12)
\n" ); document.write( "log(y) = -log(12)
\n" ); document.write( "y = -12
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\n" ); document.write( "But y cannot negative as log(-12) is meaningless.
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\n" ); document.write( "Conclusion: No solution
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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