document.write( "Question 458402: The length of a rectangle is 2cm more than the width. the perimeter is 68 cm. find the length and the width
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\n" ); document.write( "let the width of the rctangle be x cms
\n" ); document.write( "then length of the rectangle will be (x+2)cms
\n" ); document.write( "here given that primeter of the rectangle is 68 cm
\n" ); document.write( "then 2(x+x+2)=68
\n" ); document.write( "=>2*(2x+2)=68
\n" ); document.write( "=>4*(x+1)=68
\n" ); document.write( "=>x+1=17
\n" ); document.write( "=>x=16
\n" ); document.write( "hence the length of the rectangle is 18 cm and the width is 16 cm\r
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Algebra.Com's Answer #314462 by pallavi(12)\"\" \"About 
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