document.write( "Question 47594: Wow. Everyone must be on vacation this week. This'll be the 3rd time I'm posting this one, so far no answer. help, it's due by tomorrow... =)\r
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document.write( "Ride the peaks. Smith bicycled 45 miles going east from Durango, and Jones bicycled 70 miles. Jones averaged 5 miles per hour more than Smith, and his trip took one-half hour longer than Smith’s. How fast was each one traveling?\r
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document.write( "Thanks \n" );
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Algebra.Com's Answer #31441 by checkley71(8403)![]() ![]() ![]() You can put this solution on YOUR website! 45/X+.5=70/(X+5) OR (45+.5X)/X=70/(X+5) OR 70X=45X+.5X~2+225+2.5X OR\r \n" ); document.write( "\n" ); document.write( ".5X~2-22.5X+225=O OR X~2-45X+450)OR (X-15)(X-30)=0 OR X=15 & X=30 \r \n" ); document.write( "\n" ); document.write( "PROOF 45/15+.5=70/(15+5) OR 3+.5=3.5 OR 3.5=3.5\r \n" ); document.write( "\n" ); document.write( "SMITHS SPEED WAS 15 MPH & JONES WAS 15+5=20 MPH. \n" ); document.write( " |