document.write( "Question 458320: Y=0.15X-28 \n" ); document.write( "
Algebra.Com's Answer #314407 by richwmiller(17219)\"\" \"About 
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Solved by pluggable solver: DESCRIBE a linear EQUATION: slope, intercepts, etc
Equation \"0.15+x+%2B+-1+y+=+28\" describes a sloping line. For any
\n" ); document.write( " equation ax+by+c = 0, slope is \"-a%2Fb+=+-0.15%2F-1\".
  • X intercept is found by setting y to 0: ax+by=c becomes ax=c. that means that x = c/a. 28/0.15 = 186.666666666667.
  • Y intercept is found by setting x to 0: the equation becomes by=c, and therefore y = c/b. Y intercept is 28/-1 = -28.
  • Slope is -0.15/-1 = 0.15.
  • Equation in slope-intercept form: y=0.15*x+-28.
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